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Ho un file XML chiamato /NewFile.xml nella directory D :. Il file XML contiene i seguenti dati:Perché il nome dell'entità deve seguire immediatamente la '&' nel riferimento all'entità che appare per l'XML?
<?xml version="1.0"?>
<project>
<logindetails id="1001">
\t \t <url>https:xxx</url>
<username>xxx</username>
<password>xxx</password>
</logindetails >
<kpi id="1001">
\t \t <id_r>reports</id_r>
\t \t <id_e>extranet</id_e>
\t \t <id_pr>ext-pr</id_pr>
</kpi> \t
<prkpi id="1001">
<id_1>ext-pr-backlog-age</id_1>
\t \t <id_2>ext-timetoassign-prs</id_2>
\t \t <id_3>ext-timetodeliver-prs</id_3>
\t \t <id_4>ext-timetoresolve-prs</id_4>
\t \t <id_5>ext-new-prs</id_5>
</prkpi>
<filtersection id="1001">
\t \t <visualizationId>Day,Week,Month,Quarter,Semester,Year,RD Tech Group,ICC,Center,Software Pack,Product,Project,Customer PRs,Severity,Priority</visualizationId>
\t \t <projectId>dev/v4.3/r4/e12sqq,BATS,1523 Business IAD & Business CPE,[CoCo2M],VQM</projectId>
</filtersection>
</project>Il seguente codice che sto correndo in Eclipse come segue:
import java.io.File;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Properties;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.apache.log4j.Logger;
import org.apache.log4j.xml.DOMConfigurator;
import org.openqa.selenium.By;
import org.openqa.selenium.JavascriptExecutor;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.firefox.FirefoxDriver;
import org.openqa.selenium.interactions.Actions;
import org.openqa.selenium.support.ui.Select;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
public class A {
static Properties p= new Properties();
String url=p.getProperty("url");
private static Logger Log = Logger.getLogger(A.class.getName());
public static void main(String[] args) throws SAXException, IOException, ParserConfigurationException, InterruptedException {
\t WebDriver driver = new FirefoxDriver();
A a = new A();
\t Actions actions = new Actions(driver);
\t DOMConfigurator.configure("src/log4j.xml");
String url = a.readXML("logindetails","url");
String username = a.readXML("logindetails","username");
String password = a.readXML("logindetails","password");
//use username for webdriver specific actions
Log.info("Sign in to the OneReports website");
driver.manage().window().maximize();
driver.get(url);
Thread.sleep(5000);
Log.info("Enter Username");
driver.findElement(By.id("loginUsername")).sendKeys(username);
Log.info("Enter Password");
driver.findElement(By.id("loginPassword")).sendKeys(password);
//submit
Log.info("Submitting login details");
waitforElement(driver,120 , "//*[@id='submit']");
driver.findElement(By.id("submit")).submit();
Thread.sleep(5000);
\t \t Log.info("Clicking on Reports link");
\t String id_r = a.readXML("kpi","id_r");
\t WebElement menuHoverLink = driver.findElement(By.id(id_r));
\t \t \t actions.moveToElement(menuHoverLink).perform();
\t \t \t Thread.sleep(6000);
\t \t
\t \t String id_e = a.readXML("kpi","id_e");
\t \t WebElement menuHoverLink1 = driver.findElement(By.id(id_e));
\t \t actions.moveToElement(menuHoverLink1).perform();
\t \t Thread.sleep(6000);
\t \t
\t \t String id_pr = a.readXML("kpi","id_pr");
\t \t WebElement menuHoverLink2 = driver.findElement(By.id(id_pr));
\t \t actions.moveToElement(menuHoverLink2).perform();
\t \t Thread.sleep(6000);
\t \t
\t \t String id_1 = a.readXML("prkpi","id_1");
\t \t WebElement menuHoverLink3 = driver.findElement(By.id(id_1));
\t \t actions.moveToElement(menuHoverLink3).click().perform();
\t \t Thread.sleep(6000);
\t \t
}
\t private static void waitforElement(WebDriver driver, int i, String string) {
\t \t // TODO Auto-generated method stub
\t \t
\t }
\t public String readXML(String searchelement,String tag) throws SAXException, IOException, ParserConfigurationException{
String ele = null;
File fXmlFile = new File("D://NewFile.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
NodeList nList = doc.getElementsByTagName(searchelement);
Node nNode = nList.item(0);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
\t Element eElement = (Element) nNode;
ele=eElement.getElementsByTagName(tag).item(0).getTextContent();
}
return ele;
}
}Quando si esegue questo codice Sto ottenendo il seguente errore nella console come segue:
Fatal Error] NewFile.xml:27:57: The entity name must immediately follow the '&' in the entity reference.
Exception in thread "main" org.xml.sax.SAXParseException; systemId: file:/D:/NewFile.xml; lineNumber: 27; columnNumber: 57; The entity name must immediately follow the '&' in the entity reference.
\t at org.apache.xerces.parsers.DOMParser.parse(Unknown Source)
\t at org.apache.xerces.jaxp.DocumentBuilderImpl.parse(Unknown Source)
\t at javax.xml.parsers.DocumentBuilder.parse(Unknown Source)
\t at A.readXML(A.java:94)
\t at A.main(A.java:40)Vi prego di dare una soluzione a questo problema ..
Post che file XML, o per lo meno la linea 27. Probabilmente avete un escape 'e' in là, proprio come dice il messaggio. – chrylis
@chrylis Ho pubblicato il file XML completo – Amirdha
Ho scoperto che sta accadendo a causa del projectId in xml che ha & .. Ma c'è un modo per analizzarlo in XML .. – Amirdha