Modello di cella condivisa GridView WPF per tutte le colonne

Question

Sto tentando di creare un DataTemplate che può essere condiviso per tutte le colonne di un GridView, che ha le sue colonne create dinamicamente (tramite code-behind).

Vorrei creare lo DataTemplate come risorsa in XAML anziché interamente nel code-behind, ma non riesco a capire come far funzionare correttamente i binding.

Il seguente è il più vicino ho potuto venire con (ma non funziona):

<DataTemplate x:Key="ListViewCellTemplate"> 
     <TextBlock Text="{Binding RelativeSource={RelativeSource AncestorType={x:Type GridViewColumn}}}" /> 
    </DataTemplate> 

Questo modello viene assegnato come CellTemplate di ogni colonna come segue:

BindableDataTable table = this.DataContext as BindableDataTable; 

      foreach (BindableDataColumn c in table.Columns) 
      { 
       GridViewColumn col = new GridViewColumn(); 
       col.Header = c.ColumnName; 

       col.CellTemplate = this.FindResource("ListViewCellTemplate") as DataTemplate; 
       v.Columns.Add(col); 
      } 

Answer 1

I' avendo lo stesso identico problema

Desidero essere in grado di applicare il modello di dati a colonne diverse ma avere ciascuna colonna associata a un campo dati separato.

<ListView ItemsSource="{Binding}" Name="listViewIMS" Grid.Row="1" Margin="0,0,0,4" FontSize="11" AlternationCount="2" SelectionMode="Extended"> 

     <ListView.Resources> 
      <DataTemplate x:Key="Templ"> 
       <TextBlock TextAlignment="Left" Text="{Binding}"/> 
      </DataTemplate> 
      <DataTemplate x:Key="Tempr"> 
       <TextBlock Width="78" Margin="-6,0" TextAlignment="Right" Text="{Binding}" /> 
      </DataTemplate> 
      <Style x:Key="HeaderStyleRight" TargetType="GridViewColumnHeader"> 
       <Setter Property="HorizontalContentAlignment" Value="Right"/> 
      </Style> 
      <Style x:Key="HeaderStyleLeft" TargetType="GridViewColumnHeader"> 
       <Setter Property="HorizontalContentAlignment" Value="Left"/> 
      </Style>     
     </ListView.Resources> 

     <ListView.View> 
      <GridView x:Name="gridViewInvoices"> 
       <GridViewColumn Width="80" DisplayMemberBinding="{Binding Document}"> 
        <GridViewColumnHeader Tag="docNo" Content="Document" /> 
       </GridViewColumn>     
       <GridViewColumn Width="220" DisplayMemberBinding="{Binding Customer}"> 
        <GridViewColumnHeader Tag="customer" Content="Customer"/> 
       </GridViewColumn> 
       <GridViewColumn Width="100" DisplayMemberBinding="{Binding inv_date, StringFormat='dd/MM/yy'}" > 
        <GridViewColumnHeader Tag="date" Content="Date" /> 
       </GridViewColumn> 
       <GridViewColumn Width="100" DisplayMemberBinding="{Binding inv_l_catalogue}" > 
        <GridViewColumnHeader Tag="catalogue" Content="Item" /> 
       </GridViewColumn> 
       <GridViewColumn Width="60" DisplayMemberBinding="{Binding inv_l_qty}" > 
        <GridViewColumnHeader Tag="qty" Content="Qty" /> 
       </GridViewColumn> 
       <GridViewColumn Width="80" DisplayMemberBinding="{Binding inv_l_price, StringFormat='0.00' }" > 
        <GridViewColumnHeader Tag="unitPrice" Content="Price" /> 
       </GridViewColumn> 
       <GridViewColumn Width="50" DisplayMemberBinding="{Binding inv_l_per}" > 
        <GridViewColumnHeader Tag="per" Content="Per" /> 
       </GridViewColumn> 
       <GridViewColumn Header="Goods" CellTemplate ="{StaticResource Tempr}" HeaderContainerStyle="{StaticResource HeaderStyleRight}" Width="80" > 

        <!--GridViewColumn.CellTemplate> 
         <DataTemplate> 
          <TextBlock Width="78" Margin="-6,0" TextAlignment="Right" Text="{Binding inv_l_lgoods2, StringFormat='0.00'}" /> 
         </DataTemplate> 
        </GridViewColumn.CellTemplate>--> 
       </GridViewColumn> 
      </GridView> 
     </ListView.View> 

    </ListView> 

Answer 2

Risposta:

Impostare un DataTemplate nelle risorse

<UserControl.Resources> 
     <ResourceDictionary> 
      <DataTemplate x:Key="GridViewCellTemplateStyle"> 
       <TextBlock Text="{Binding}"> 
        <TextBlock.InputBindings> 
         <MouseBinding Gesture="LeftDoubleClick" Command="{Binding DataContext.CommandDoubleClick, RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type ListView}}}"/> 
        </TextBlock.InputBindings> 
       </TextBlock> 
      </DataTemplate> 
     </ResourceDictionary> 
    </UserControl.Resources> 

Crea il tuo vista griglia e rendere le colonne ereditano questa DataTemplate

<ListView> 
      <ListView.View> 
       <GridView> 
        <GridViewColumn Width="Auto" Header="Column1" CellTemplate="{StaticResource GridViewCellTemplateStyle}"/> 
        <GridViewColumn Width="Auto" Header="Column2" CellTemplate="{StaticResource GridViewCellTemplateStyle}"/> 
        <GridViewColumn Width="Auto" Header="Column3" CellTemplate="{StaticResource GridViewCellTemplateStyle}"/> 
        <GridViewColumn Width="Auto" Header="Column4" CellTemplate="{StaticResource GridViewCellTemplateStyle}"/> 
       </GridView> 
      </ListView.View> 
     </ListView> 

Questo exmaple mostra come creare una doppia riga selezionabile in una GridViewColumn. Basta modificare il DataTemplate come meglio credi