Django: come visualizzare gli errori di modulo per ogni oggetto del modello in un set di forme in linea

Question

Ho un modello di autore e un modello di libri. Un utente può modificare le proprietà di tutti i libri di un determinato autore. Voglio essere in grado di visualizzare gli errori per ogni singolo libro piuttosto che avere tutti gli errori elencati in alto, Come posso fare questo?

MODELLI

from django.db import models 
from django.forms import ModelForm, Textarea 
from django import forms 

class Author(models.Model): 
    fname = models.CharField(max_length=100) 
    lname = models.CharField(max_length=100) 
    def fullname(self): 
     return '%s %s' % (self.fname, self.lname) 
    fullname = property(fullname) 
    def __unicode__(self): 
     return self.fullname 

class Books(models.Model): 
    author = models.ForeignKey(Author) 
    title = models.CharField(max_length=50) 
    publisher = models.CharField(max_length=50) 
    edition = models.CharField(max_length=50) 
    comment = models.TextField() 
    def __unicode__(self): 
     return self.title 

VISTA

def author_books_edit(request, author_id): 
    a = get_object_or_404(Author, pk=author_id) 
    authorsbooks = a.books_set.all() 
    bookformset = inlineformset_factory(Author, Books, can_delete=True, can_order=True, exclude=('company',), extra=1) 
    formset = bookformset(instance=a) 
    if request.method == "POST": 
     formset = bookformset(request.POST, request.FILES, instance=a) 
     if formset.is_valid(): 
      formset.save() 
     else: 
      form_errors = formset.errors 
      return render_to_response('test/authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset, 'form_errors': form_errors}, context_instance=RequestContext(request)) 
    return render_to_response('test/authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset,}, context_instance=RequestContext(request)) 

MODELLO

#all errors are here 
{% for dict in form_errors %} 
    {{ dict }} 
{% endfor %} 

#all forms are here, i want to pair the errors for each form 
<form method="post" action="/test/{{ author.id }}/books/"> 
    {% csrf_token %} 
     <table> 
     {{ formset }} 
     </table> 
    <input type="submit" value="Submit"/> 
    </form> 

modello aggiornato: non visualizza errori

<form method="post" action="/test/{{ author.id }}/books/"> 
    {% formset.management_form %} 
    {% csrf_token %} 
    <table> 
     {% for x in formset %} 
     {{x.errors }} 
     {{ x }} 
     {% endfor %} 
    </table> 
<input type="submit" value="Submit"/> 

Answer 1

EDIT

authors_books_edits.html

<form method="post" action="/test/{{ author.id }}/books/"> 
    {% csrf_token %} 
    {{ formset.management_form }} 
    {% for form in formset.forms %} 
     {{ form.non_field_errors }} 
     {{ form.errors }} 
     <table> 
      {{ form.as_table }} 
     </table> 
    {% endfor %} 
    <input type="submit" value="Submit"/> 
</form> 

views.py

from django.shortcuts import * 
from django.forms.models import inlineformset_factory 

from .models import * 

def author_books_edit(request, author_id): 
    a = get_object_or_404(Author, pk=author_id) 
    authorsbooks = a.books_set.all() 
    bookformset = inlineformset_factory(Author, Books, can_delete=True, can_order=True, exclude=('company',), extra=1) 
    formset = bookformset(instance=a) 
    if request.method == "POST": 
     formset = bookformset(request.POST, request.FILES, instance=a) 
     if formset.is_valid(): 
      formset.save() 
     else: 
      form_errors = formset.errors 
      return render_to_response('authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset, 'form_errors': form_errors}, context_instance=RequestContext(request)) 
    return render_to_response('authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset,}, context_instance=RequestContext(request)) 

models.py

from django.db import models 

class Author(models.Model): 
    fname = models.CharField(max_length=100) 
    lname = models.CharField(max_length=100) 
    def fullname(self): 
     return '%s %s' % (self.fname, self.lname) 
    fullname = property(fullname) 
    def __unicode__(self): 
     return self.fullname 

class Books(models.Model): 
    author = models.ForeignKey(Author) 
    title = models.CharField(max_length=50) 
    publisher = models.CharField(max_length=50) 
    edition = models.CharField(max_length=50) 
    comment = models.TextField() 
    def __unicode__(self): 
     return self.title 

urls.py

from django.conf.urls.defaults import patterns, include, url 

urlpatterns = patterns('testapp.views', 
    url(r'test/(?P<author_id>\d+)/books/$', 'author_books_edit'), 
) 

È possibile effettuare un'altra app temporanea per testarlo.

Ecco come si presenta: http://imageshack.us/photo/my-images/824/screenshotat20120227190.png/

END == EDIT

È possibile iterare forme come ad esempio:

{% for form in formset.forms %} 
    {{ form }} 
{% endfor %} 

In questo caso, fare riferimento a Django di visualizzazione di un modulo utilizzando un modello documentazione: https://docs.djangoproject.com/en/dev/topics/forms/#displaying-a-form-using-a-template

Quindi, più interessante, la personalizzazione di un modello di modulo (vedere form.non_field_errors): https://docs.djangoproject.com/en/dev/topics/forms/#customizing-the-form-template

Answer 2

Supponendo che il libro è una forma che si possa fare:

{% for b in authorsbooks %} 
    {{b.errors}} 
{% endfor %}