Ho trovato questa espressione regolare su un sito Web. Si dice che sia la migliore espressione di convalida degli URL là fuori e sono d'accordo. Diego Perini lo ha creato.NSRegularExpression per convalidare l'URL
Il problema che sto affrontando è quando si prova ad usarlo con objective-C per rilevare gli URL sulle stringhe. Ho provato a utilizzare opzioni come NSRegularExpressionAnchorsMatchLines, NSRegularExpressionIgnoreMetacharacters e altri, ma ancora senza fortuna.
L'espressione non è formattata correttamente per Objective-C? Mi sto perdendo qualcosa? Qualche idea?
Ho anche provato la regex di John Gruber, ma non riesce con alcuni URL non validi.
Regular Expression Explanation of expression
^ match at the beginning
//Protocol identifier
(?:
(?:https?|ftp http, https or ftp
):\\/\\/ ://
)? optional
// User:Pass authentication
(?:
^\\s+ non white spaces, 1 or more times
(?:
:^\\s* : non white spaces, 0 or more times, optionally
)[email protected] @
)? optional
//Private IP Addresses ?! Means DO NOT MATCH ahead. So do not match any of the following
(?:
(?!10 10 10.0.0.0 - 10.999.999.999
(?:
\\.\\d{1,3} . 1 to 3 digits, three times
){3}
)
(?!127 127 127.0.0.0 - 127.999.999.999
(?:
\\.\\d{1,3} . 1 to 3 digits, three times
){3}
)
(?!169\\.254 169.254 169.254.0.0 - 169.254.999.999
(?:
\\.\\d{1,3} . 1 to 3 digits, two times
){2}
)
(?!192\\.168 192.168 192.168.0.0 - 192.168.999.999
(?:
\\.\\d{1,3} . 1 to 3 digits, two times
){2}
)
(?!172\\. 172. 172.16.0.0 - 172.31.999.999
(?:
1[6-9] 1 followed by any number between 6 and 9
| or
2\\d 2 and any digit
| or
3[0-1] 3 followed by a 0 or 1
)
(?:
\\.\\d{1,3} . 1 to 3 digits, two times
){2}
)
//First Octet IPv4 // match these. Any non network or broadcast IPv4 address
(?:
[1-9]\\d? any number from 1 to 9 followed by an optional digit 1 - 99
| or
1\\d\\d 1 followed by any two digits 100 - 199
| or
2[01]\\d 2 followed by any 0 or 1, followed by a digit 200 - 219
| or
22[0-3] 22 followed by any number between 0 and 3 220 - 223
)
//Second and Third Octet IPv4
(?:
\\. .
(?:
1?\\d{1,2} optional 1 followed by any 1 or two digits 0 - 199
| or
2[0-4]\\d 2 followed by any number between 0 and 4, and any digit 200 - 249
| or
25[0-5] 25 followed by any numbers between 0 and 5 250 - 255
)
){2} two times
//Fourth Octet IPv4
(?:
\\. .
(?:
[1-9]\\d? any number between 1 and 9 followed by an optional digit 1 - 99
| or
1\\d\\d 1 followed by any two digits 100 - 199
| or
2[0-4]\\d 2 followed by any number between 0 and 4, and any digit 200 - 249
| or
25[0-4] 25 followed by any number between 0 and 4 250 - 254
)
)
//Host name
| or
(?:
(?:
[a-z\u00a1-\uffff0-9]+-? any letter, digit or character one or more times with optional -
)* zero or more times
[a-z\u00a1-\uffff0-9]+ any letter, digit or character one or more times
)
//Domain name
(?:
\\. .
(?:
[a-z\u00a1-\uffff0-9]+-? any letter, digit or character one or more times with optional -
)* zero or more times
[a-z\u00a1-\uffff0-9]+ any letter, digit or character one or more times
)* zero or more times
//TLD identifier
(?:
\\. .
(?:
[a-z\u00a1-\uffff]{2,} any letter, digit or character more than two times
)
)
)
//Port number
(?:
:\\d{2,5} : followed by any digit, two to five times, optionally
)?
//Resource path
(?:
\\/[^\\s]* /followed by an optional non space character, zero or more times
)? optional
$ match at the end
EDIT penso Ho dimenticato di dire che sto usando l'espressione nel codice seguente: (codice parziale)
NSError *error = NULL;
NSRegularExpression *detector = [NSRegularExpression regularExpressionWithPattern:[self theRegularExpression] options:0 error:&error];
NSArray *links = [detector matchesInString:theText options:0 range:NSMakeRange(0, theText.length)];
Grazie amico per il bel post. – Jhaliya
Il tuo codice gruber aggiornato è buono, ma non corrisponde a "google.com", ma corrisponde a "google.comm" e "google.co.uk": qualche idea su come modificarla? – mootymoots
Amico molte grazie per l'espressione regolare. È davvero incredibile. –