Elenco alfabetico di gruppo in ordine alfabetico in php

Question

Ho una tabella membro in cui sto memorizzando tutti i dettagli su un membro compreso il suo nome, email, telefono ecc. Voglio che il nome apparirà come un gruppo alfabetico saggio. Come mostrato nell'esempio.

Posso ordinare il campo in ordine alfabetico utilizzando l'ordine di ASC ma come ottenerli in un gruppo di alfabeto.

Tutti i suggerimenti sono i benvenuti. Sto usando php.

Answer 1

si può fare con la query di selezione come in questo esempio:

$query = "SELECT * FROM `user` ORDER BY `name` ASC ;"; 

Answer 2

forse è un brutto modo di farlo, ma può aiutare a ora.

<?php 

    $aGroup = array(
     "A" => array(), 
     "B" => array(), 
     "C" => array(), 
     "D" => array(), 
     "E" => array(), 
     // until "Z" 
     ); 

    $result = mysql_query("SQL as you want"); 

    while ($row = mysql_fetch_array($result)) { 
     $letter = strtoupper($row[0][0]); // I supose that the first column is the name 
     $aGroup[$letter][] = $row; 
    } 

?> 

Answer 3

Questa domanda dovrebbe avere la risposta - How to display an Array under alphabetical letters using PHP?

risposta selezionata:

$previous = null; 
foreach($array as $value) { 
    $firstLetter = substr($value, 0, 1); 
    if($previous !== $firstLetter) echo "\n".$firstLetter."\n---\n\n"; 
    $previous = $firstLetter; 

    echo $value."\n"; 
} 

Answer 4

Se si vuole fare questo, all'interno del vostro SQL;

SELECT SUBSTRING(name, 1, 1) as alpha, name from 'user' GROUP BY SUBSTRING(name, 0, 2), name order by 'alpha', 'name' 

e in php

<?php 

    $temp = array(); // would also generate a dynamic array 
    $result = mysql_query("SELECT SUBSTRING(name, 1, 1) as alpha, name from 'user' GROUP BY SUBSTRING(name, 0, 2), name order by 'alpha', 'name'" 
    while ($row = mysql_fetch_array($result)) { 
     $temp[$row['alpha']][] = $row['name']; 
    } 

    /* this would create array such as; 

    'A' 
     --> 'Adam' 
     --> 'Apple' 
    'B' 
     --> 'Ba...' 
     --> 'Be...' 
    */ 

?> 

Spero che questo aiuti.

Answer 5

try this 
/* Get the letter user clicked on and assign it a variable called $sort */ 
$sort = $_REQUEST['letter']; 
/* Let's check if variable $sort is empty. If it is we will create a query to display all customers alphabetically ordered by last name. */ 
if($sort == ""){ 
$qry= "SELECT * FROM tbl_customers ORDER BY lastname ASC "; 
}else{ 
/* if varible $sort is not empty we will create a query that sorts out the customers by their last name, and order the selected records ascendingly. */ 
$qry = "SELECT * FROM tbl_customers WHERE lastname LIKE '$sort%' ORDER BY lastname ASC"; 
} 
/* Notice the use of '%' wilde card in the above query "LIKE '$sort%'". */ 
//next step is to execute the query. 
$execute = mysql_query($qry) or die(mysql_error()); 
/* Before we display results let's create our alphabetical navigation. The easiest way to create the navigation is to use character codes and run them through the "for" loop. */ 
echo "<p>"; 
for ($i = 65; $i < 91; $i++) { 
printf('<a href="%s?letter=%s">%s</a> | ', 
$PHP_SELF, chr($i), chr($i)); 
} 
echo "</p>"; 
/* now we are ready to display the results. Since out tbl_customers table has only three fileds we will display the results in a paragraphs. In the real world you may need to display the results in a table. 
To display the results we will use "do while" loop to fetch the results. If no customers are found we will display an error message. */ 
if(mysql_num_rows($execute)>0){ 
do{ 
echo "<p>" .$result['id']. " " .$result['firstname']. " " .$result['lastname']. "</p>"; 
}while($result = mysql_fetch_assoc($execute)); 
}else{ 
echo "<p>No customer found.</p>"; 
}