Sulla Christopher Bruns risposta, così come il script from "How to create Mac application bundle for Python script via Python", ecco un Script Python che crea un pacchetto (app) per uno script Python utente, che mostrerà il nome dell'app anziché "Python" nei menu. Per fare questo, cerca di localizzare una versione in bundle di Python, e symlink con il nome dell'app. L'ho provato con uno script wxpython, ma dovrebbe funzionare anche per Qt.
Lo script utente viene eseguito dalla posizione originale anziché collocarlo nell'app. Se si desidera posizionare gli script in un pacchetto (insieme a python) per la ridistribuzione, vedere invece py2app.
#!/usr/bin/env python
'''This creates an app to launch a python script. The app is
created in the directory where python is called. A version of Python
is created via a softlink, named to match the app, which means that
the name of the app rather than Python shows up as the name in the
menu bar, etc, but this requires locating an app version of Python
(expected name .../Resources/Python.app/Contents/MacOS/Python in
directory tree of calling python interpreter).
Run this script with one or two arguments:
<python script>
<project name>
The script path may be specified relative to the current path or given
an absolute path, but will be accessed via an absolute path. If the
project name is not specified, it will be taken from the root name of
the script.
'''
import sys, os, os.path, stat
def Usage():
print("\n\tUsage: python "+sys.argv[0]+" <python script> [<project name>]\n")
sys.exit()
version = "1.0.0"
bundleIdentifier = "org.test.test"
if not 2 <= len(sys.argv) <= 3:
Usage()
script = os.path.abspath(sys.argv[1])
if not os.path.exists(script):
print("\nFile "+script+" not found")
Usage()
if os.path.splitext(script)[1].lower() != '.py':
print("\nScript "+script+" does not have extension .py")
Usage()
if len(sys.argv) == 3:
project = sys.argv[2]
else:
project = os.path.splitext(os.path.split(script)[1])[0]
# find the python application; must be an OS X app
pythonpath,top = os.path.split(os.path.realpath(sys.executable))
while top:
if 'Resources' in pythonpath:
pass
elif os.path.exists(os.path.join(pythonpath,'Resources')):
break
pythonpath,top = os.path.split(pythonpath)
else:
print("\nSorry, failed to find a Resources directory associated with "+str(sys.executable))
sys.exit()
pythonapp = os.path.join(pythonpath,'Resources','Python.app','Contents','MacOS','Python')
if not os.path.exists(pythonapp):
print("\nSorry, failed to find a Python app in "+str(pythonapp))
sys.exit()
apppath = os.path.abspath(os.path.join('.',project+".app"))
newpython = os.path.join(apppath,"Contents","MacOS",project)
projectversion = project + " " + version
if os.path.exists(apppath):
print("\nSorry, an app named "+project+" exists in this location ("+str(apppath)+")")
sys.exit()
os.makedirs(os.path.join(apppath,"Contents","MacOS"))
f = open(os.path.join(apppath,"Contents","Info.plist"), "w")
f.write('''<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
<key>CFBundleDevelopmentRegion</key>
<string>English</string>
<key>CFBundleExecutable</key>
<string>main.sh</string>
<key>CFBundleGetInfoString</key>
<string>{:}</string>
<key>CFBundleIconFile</key>
<string>app.icns</string>
<key>CFBundleIdentifier</key>
<string>{:}</string>
<key>CFBundleInfoDictionaryVersion</key>
<string>6.0</string>
<key>CFBundleName</key>
<string>{:}</string>
<key>CFBundlePackageType</key>
<string>APPL</string>
<key>CFBundleShortVersionString</key>
<string>{:}</string>
<key>CFBundleSignature</key>
<string>????</string>
<key>CFBundleVersion</key>
<string>{:}</string>
<key>NSAppleScriptEnabled</key>
<string>YES</string>
<key>NSMainNibFile</key>
<string>MainMenu</string>
<key>NSPrincipalClass</key>
<string>NSApplication</string>
</dict>
</plist>
'''.format(projectversion, bundleIdentifier, project, projectversion, version)
)
f.close()
# not sure what this file does
f = open(os.path.join(apppath,'Contents','PkgInfo'), "w")
f.write("APPL????")
f.close()
# create a link to the python app, but named to match the project
os.symlink(pythonapp,newpython)
# create a script that launches python with the requested app
shell = os.path.join(apppath,"Contents","MacOS","main.sh")
# create a short shell script
f = open(shell, "w")
f.write('#!/bin/sh\nexec "'+newpython+'" "'+script+'"\n')
f.close()
os.chmod(shell, os.stat(shell).st_mode | stat.S_IXUSR | stat.S_IXGRP | stat.S_IXOTH)
Come stai iniziando il tuo programma?So molto poco dei mac, ma sembra che stia semplicemente mettendo il valore di sys.argv [0] lì. – Falmarri
Inizio il programma digitando "python MyApp.py" o "./MyApp.py". In entrambi i casi, sys.argv [0] è "MyApp.py" o "./MyApp.py". "Python" non fa parte di argv. –
@Christpher Bruns: Hmm, hai ragione. Non so perché pensavo che l'argv di python avesse dato a python il suo 'argv [0]'. Però non conosco quasi niente di mac, quindi sono tutto fuori di idee. – Falmarri