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Question

Forse mi aiuterete con la mia query sql. La mia domanda si basa su un'altra domanda è qui: Mysql | Faceted search Tutto è uguale e ho bisogno dello stesso risultato ma le tabelle sono leggermente diverse. Non riesco a costruire la mia domanda. Si prega di dare un'occhiata a questo sql fiddle:

La mia struttura della tabella:

CREATE TABLE products 
    (`id` int, `description` varchar(9), `user_id` int); 

INSERT INTO products 
    (`id`, `description`, `user_id`) 
VALUES 
    (1, 'my car', 3), 
    (2, 'dream car', 3), 
    (3, 'New car', 3), 
    (4, 'Old car', 4); 

CREATE TABLE fields 
    (`id` int, `field_name` varchar(14)); /*meta_name*/ 

INSERT INTO fields 
    (`id`, `field_name`) 
VALUES 
    (1, 'Make'), 
    (2, 'Model'), 
    (3, 'Color'), 
    (4, 'Car Type'), 
    (5, 'Interior Color'); 

CREATE TABLE fields_values 
    (`id` int, `field_id` int, `field_value` varchar(7)); /*meta_value*/ 

INSERT INTO fields_values 
    (`id`, `field_id`, `field_value`) 
VALUES 
    (1, 1, 'BMW'), 
    (2, 2, '3Series'), 
    (3, 3, 'White'), 
    (4, 4, 'Coupe'), 
    (5, 5, 'Black'), 
    (6, 1, 'BMW'), 
    (7, 2, '2Series'), 
    (8, 3, 'Black'), 
    (9, 4, 'Coupe'), 
    (10, 5, 'Grey'), 
    (11, 1, 'Honda'), 
    (12, 2, 'Civic'), 
    (13, 3, 'Red'), 
    (14, 4, 'Sedan'), 
    (15, 5, 'Black'); 

CREATE TABLE products2fields_values 
    (`id` int, `product_id` int, `field_value_id` int); 
INSERT INTO products2fields_values 
    (`id`, `product_id`, `field_value_id`) 
VALUES 
    (1, 1, 1), 
    (2, 1, 2), 
    (3, 1, 3), 
    (4, 1, 4), 
    (5, 1, 5), 
    (6, 2, 1), 
    (7, 2, 2), 
    (8, 2, 3), 
    (9, 2, 4), 
    (10, 2, 5), 
    (11, 3, 1), 
    (12, 3, 2), 
    (13, 3, 3), 
    (14, 3, 4), 
    (15, 3, 5); 

E la mia domanda sbagliata:

SELECT field_name, field_value, COUNT(DISTINCT pid) count 
FROM fields ft 
JOIN fields_values fvt 
    ON fvt.field_id = ft.id 

JOIN products2fields_values p2fv 
    ON p2fv.field_value_id = fvt.id 

LEFT JOIN (
    SELECT p.id pid 
    FROM products p 
    JOIN products2fields_values p2fv 
     ON p2fv.product_id = p.id 
    JOIN fields_values fvt 
     ON fvt.id = p2fv.field_value_id 
    JOIN fields ft 
     ON ft.id = fvt.field_id 
    GROUP BY p.id 
    HAVING MAX(ft.id = 1 AND p2fv.field_value_id = 1) = 1 
     AND MAX(ft.id = 4 AND p2fv.field_value_id = 4) = 1 
) 

LJ ON p2fv.product_id = LJ.pid 
GROUP BY field_name, field_value; 

Sto cercando di ottenere il risultato:

|  field_name| field_value| count | 
|----------------|------------|-------| 
|  Car Type |  Coupe |  2 | 
|  Car Type |  Sedan |  0 | 
|   Color |  Black |  1 | 
|   Color |  Red |  0 | 
|   Color |  White |  1 | 
| Interior Color |  Black |  2 | 
| Interior Color |  Grey |  1 | 
|   Make |  BMW |  2 | 
|   Make |  Honda |  0 | 
|   Model | 2Series |  0 | 
|   Model | 3Series |  1 | 
|   Model |  Civic |  0 | 

Answer 1

Per quanto ho capito la tua domanda a questo dovrebbe essere la query che si desidera:

SELECT field_name, field_value, COUNT(val.id) as count 
FROM fields ft 
JOIN fields_values fvt 
ON fvt.field_id = ft.id 
LEFT JOIN products2fields_values val 
ON val.field_value_id = fvt.id 
GROUP BY field_name, field_value; 

Non so il motivo per cui si stanno unendo la vostra tavola prodotto perché non sembra essere necessaria per i risultati. E non capisco perché hai implementato la tua strana clausola HAVING.

Si prega di dare un'occhiata ai risultati della mia richiesta.

Answer 2

È necessario correggere i dati per la colonna field_value_id nella tabella products2fields_values.

Con i dati correnti, le relazioni della tabella si sono interrotte e non possiamo ottenere risultati attesi con quei valori seduti lì.

Inserire dovrebbe essere come di seguito:

INSERT INTO products2fields_values 
    (id, product_id, field_value_id) 
VALUES 
    (1,1, 1), 
    (2,1, 2), 
    (3,1, 3), 
    (4,1, 4), 
    (5,1, 5), 
    (6,2, 6), 
    (7,2, 7), 
    (8,2, 8), 
    (9,2, 9), 
    (10,2, 10), 
    (11,3, 11), 
    (12,3, 12), 
    (13,3, 13), 
    (14,3, 14), 
    (15,3, 15); 

esecuzione di query di seguito come suggerito da @steven dovrebbe dare i risultati attesi:

SELECT 
    field_name, field_value, COUNT(val.id) as count 
FROM 
    fields ft 
INNER JOIN 
    fields_values fvt ON fvt.field_id = ft.id 
LEFT JOIN 
    products2fields_values val ON val.field_value_id = fvt.id 
GROUP BY field_name, field_value; 

You can see results here

Answer 3

sono riuscito ad ottenere la soluzione per questo nella mia istanza di SQL Server 2014 per Pivoting le tabelle in una nuova tabella e utilizzando questo con alcuni organismi come mostrato di seguito:

Declare @Make varchar(7) 
Declare @CarType varchar(7) 

Create table #CarDetails (CarId int, Make varchar(7), Model varchar(7), Colour varchar(7), CarType varchar(7), InteriorColour varchar(7)) 
Insert into #CarDetails 
Select CarId, [1] as Make, [2] Model, [3] Colour, [4] CarType, [5] InteriorColour 
from 
(Select ROW_NUMBER() over (partition by field_id order by id asc) CarId, field_id, field_value 
from fields_values) a 
PIVOT 
(Max(field_value) for field_id in ([1],[2],[3],[4],[5])) as pvt 
order by pvt.CarId 

Set @Make = 'BMW' 
Set @CarType = 'Coupe' 

Select 'Car Type' field_name, CarType field_value, Count(CarType) [count] 
from #CarDetails 
Where Make = @Make and CarType = @CarType 
Group by CarType 
UNION 
Select 'Colour', Colour, Count(Colour) 
from #CarDetails 
Where Make = @Make and CarType = @CarType 
Group by Colour 
UNION 
Select 'Interior Colour', InteriorColour, Count(InteriorColour) 
from #CarDetails 
Where Make = @Make and CarType = @CarType 
Group by InteriorColour 
UNION 
Select 'Make', Make, Count(Make) 
from #CarDetails 
Where Make = @Make and CarType = @CarType 
Group by Make 
UNION 
Select 'Model', Model, Count(Model) 
from #CarDetails 
Where Make = @Make and CarType = @CarType 
Group by Model 

Tuttavia questo è per MySQL e MySQL non ha una funzione RowNumber né pivot funzione così Ho provato a farlo funzionare, ma sfortunatamente non sono ancora riuscito a testarlo dato che SQLFiddle sta avendo problemi. Speriamo che questo funziona:

Set @Make = 'BMW' 
Set @CarType = 'Coupe' 

Create temporary table CarDetails (CarId int, Make varchar(7), Model varchar(7), Colour varchar(7), CarType varchar(7), InteriorColour varchar(7)); 
Insert into CarDetails (CarId, Make) 
Select CarId, field_value 
from 
(Select @RowNum := @RowNum + 1 as CarId, @fieldid := field_id as field_id, field_value 
from fields_values where field_id = 1) a; 
Set @RowNum = 0; 

Update CarDetails c 
JOIN 
(Select @RowNum := @RowNum + 1 as CarId, @fieldid := field_id as field_id, field_value 
from fields_values where field_id = 2) a on a.CarId = c.CarId 
Set c.Model = a.field_value; 
Set @RowNum = 0; 

Update CarDetails c 
JOIN 
(Select @RowNum := @RowNum + 1 as CarId, @fieldid := field_id as field_id, field_value 
from fields_values where field_id = 3) a on a.CarId = c.CarId 
Set Colour = a.field_value; 
Set @RowNum = 0; 

Update CarDetails c 
JOIN 
(Select @RowNum := @RowNum + 1 as CarId, @fieldid := field_id as field_id, field_value 
from fields_values where field_id = 4) a on a.CarId = c.CarId 
Set CarType = field_value; 
Set @RowNum = 0; 

Update CarDetails c 
JOIN 
(Select @RowNum := @RowNum + 1 as CarId, @fieldid := field_id as field_id, field_value 
from fields_values where field_id = 5) a on a.CarId = c.CarId 
Set InteriorColour = field_value; 

Select 'Car Type' field_name, CarType field_value, Count(CarType) count 
from CarDetails 
Where Make = @Make and CarType = @CarType 
Group by CarType 
UNION 
Select 'Colour', Colour, Count(Colour) 
from CarDetails 
Where Make = @Make and CarType = @CarType 
Group by Colour 
UNION 
Select 'Interior Colour', InteriorColour, Count(InteriorColour) 
from CarDetails 
Where Make = @Make and CarType = @CarType 
Group by InteriorColour 
UNION 
Select 'Make', Make, Count(Make) 
from CarDetails 
Where Make = @Make and CarType = @CarType 
Group by Make 
UNION 
Select 'Model', Model, Count(Model) 
from CarDetails 
Where Make = @Make and CarType = @CarType 
Group by Model 

** Aggiornamento ** SQLFiddle è tornato su e qui si sta lavorando: http://www.sqlfiddle.com/#!9/aa769/4/2