Come ottenere somma del campo di volta in assistente 2008

Question

Sto affrontando un problema nel trovare la somma dei valori memorizzati in una colonna SQL,

Ho una tabella come questa:

gs_cycle_no | from_time | to_time | total_hours(varchar) ... 
GSC-334/2012 | 13:00  | 7:00  | 42:00 
GSC-334/2012 | 8:30  | 3:45  | 6:00 
. 
. 
. 

What i è necessario trovare il gruppo Sum(total_hours) entro il gs_cycle_no. Ma il metodo Sum non funziona sulla colonna varchar e anche i cant convertirlo in decimale grazie al suo formato,

come posso trovare la sum di total_hours colonna, sulla base di gs_cycle_no?

Answer 1

se non si hanno minuti e solo poche ore, allora si può fare qualcosa di simile:

select 
    cast(sum(cast(replace(total_hours, ':', '') as int)/100) as nvarchar(max)) + ':00' 
from Table1 
group by gs_cycle_no 

se non, provate questo:

with cte as 
(
    select 
     gs_cycle_no, 
     sum(cast(left(total_hours, len(total_hours) - 3) as int)) as h, 
     sum(cast(right(total_hours, 2) as int)) as m 
    from Table1 
    group by gs_cycle_no 
) 
select 
    gs_cycle_no, 
    cast(h + m/60 as nvarchar(max)) + ':' + 
    right('00' + cast(m % 60 as nvarchar(max)), 2) 
from cte 

sql fiddle demo

Answer 2

Questa interrogazione trova la somma in minuti:

SQLFiddle demo

select gs_cycle_no, 

    SUM(
    CAST(
    ISNULL(
    substring(total_hours,1,CHARINDEX(':',total_hours)-1) 
    ,'0') as INT) * 60 
    + 
    CAST(
    ISNULL(
    substring(total_hours,CHARINDEX(':',total_hours)+1,100) 
    ,'0') as INT) 
    ) 
    from t 
group by gs_cycle_no 

Answer 3

Ecco soluzione in cui mi rompo varchar in due piccoli pezzi, ore e minuti, e poi fare minuti da loro, e alla fine, li Somma:

SELECT 
    gs_cycle_no, 
    CAST(SUM(
     SUBSTRING(total_hours,0 ,CHARINDEX(':', total_hours)) * 60 + 
     SUBSTRING(total_hours, CHARINDEX(':', total_hours) + 1, LEN(total_hours)))/60 AS VARCHAR) + ':' + 
    CAST(SUM(
     SUBSTRING(total_hours,0 ,CHARINDEX(':', total_hours)) * 60 + 
     SUBSTRING(total_hours, CHARINDEX(':', total_hours) + 1, LEN(total_hours))) % 60 AS VARCHAR) 
FROM Table1 
GROUP BY gs_cycle_no 

Answer 4

questo funzionerà:

;with times as (
    select gs_cycle_no = 'GSC-334/2012', total_hours = '8:35' 
    union all SELECT gs_cycle_no = 'GSC-334/2012', '5:00' 
    union all SELECT gs_cycle_no = 'GSC-334/2012', '16:50' 
    union all SELECT gs_cycle_no = 'GSC-334/2012', '42:00' 
    union all SELECT gs_cycle_no = 'GSC-335/2012', '0:00' 
    union all SELECT gs_cycle_no = 'GSC-335/2012', '175:52' 
    union all SELECT gs_cycle_no = 'GSC-335/2012', '12:25') 
SELECT 
    gs_cycle_no, 
    hrs = sum(mins)/60 + sum(hrs), 
    mins = sum(mins) % 60 
FROM 
    TIMES 
    cross apply(
     select c = charindex(':', total_hours) 
    ) idx 
    cross apply(
     select 
      hrs = cast(substring(total_hours, 1, c - 1) as int), 
      mins = cast(substring(total_hours, c + 1, len(total_hours)) as int) 
    ) ext 
group by gs_cycle_no 
order by gs_cycle_no