parola contenente numeri

Question

Come posso riconoscere una parola con regex che potrebbe contenere numeri in essa contenuti. Quindi voglio catturare "string1", "12inches", "log4net". Ma non il 12/11/2011 o il 18? Unfortunetly \b[\p{L}\d\p{M}]+\b afferra anche numeri.

Answer 1

questo:

Regex regexObj = new Regex(@"\b(?=\S*[a-z])\w+\b", RegexOptions.IgnoreCase); 
    Match matchResults = regexObj.Match(subjectString); 
    while (matchResults.Success) { 
     // matched text: matchResults.Value 
     // match start: matchResults.Index 
     // match length: matchResults.Length 
     matchResults = matchResults.NextMatch(); 
    } 

viene in mente.

" 
\b   # Assert position at a word boundary 
(?=   # Assert that the regex below can be matched, starting at this position (positive lookahead) 
    \S   # Match a single character that is a “non-whitespace character” 
     *   # Between zero and unlimited times, as many times as possible, giving back as needed (greedy) 
    [a-z]  # Match a single character in the range between “a” and “z” 
) 
\w   # Match a single character that is a “word character” (letters, digits, etc.) 
    +   # Between one and unlimited times, as many times as possible, giving back as needed (greedy) 
\b   # Assert position at a word boundary 
" 

Answer 2

Vuoi abbinare una parola con lettere e numeri al suo interno? Questo dovrebbe funzionare: \b(\w+\d+|\d+\w+)[\w\d]+\b.