Loop di più array per anno

Question

Sto cercando più array ma ho problemi con l'allineamento in una tabella in base all'anno. Al momento i dati non si allineano con l'anno corrispondente, se i dati esistono in qualsiasi anno, si limitano a collocare i dati nella prima riga, quindi posiziona i dati '0' per il resto, ad es. non allineato con l'anno.

View

<table> 
<% @a.zip(@b, @c, @d) do |a, b, c, d| %> 
<tr> 
    <td><%= a.year %></td> 
    <% if a.blank? %> 
    <td>0</td> 
    <td>0</td> 
    <% else %> 
    <td><%= a.id %></td> 
    <td><%= a.data %></td> 
    <% end %> 
    <% if b.blank? %> 
    <td>0</td> 
    <td>0</td> 
    <% else %> 
    <td><%= b.id %></td> 
    <td><%= b.data %></td> 
    <% end %> 
    <% if c.blank? %> 
    <td>0</td> 
    <td>0</td> 
    <% else %> 
    <td><%= c.id %></td> 
    <td><%= c.data %></td> 
    <% end %> 
    <% if d.blank? %> 
    <td>0</td> 
    <td>0</td> 
    <% else %> 
    <td><%= d.id %></td> 
    <td><%= d.data %></td> 
    <% end %> 
</tr> 
</table> 

controller

@a = Result.where(id: params[:id_select]).group('year').where('data > 0').select('AVG(data) AS data, year as year, COUNT(id) AS id').order('year ASC') 

@b = Result.where(id: params[:id_select]).group('year').where('data > 0').select('AVG(data) AS data, year as year, COUNT(id) AS id').where('id = ?', '0').order('year ASC') 

@c = Result.where(id: params[:id_select]).group('year').where('data > 0').select('AVG(data) AS data, year as year, COUNT(id) AS id').where('id = ?', '1').order('year ASC') 

@d = Result.where(id: params[:id_select]).group('year').where('data > 0').select('AVG(data) AS data, year as year, COUNT(id) AS id').where('id = ?', '2').order('year ASC') 

Answer 1

Penso che tu possa provare in questo modo. in questo non hai bisogno di verificare i valori vuoti. spero @a contiene tutti gli anni disponibili altrimenti si ha la necessità di unire tutti gli anni un ciclo attraverso anni

<table> 
<% @a.each do |a| %> 
<tr> 
    <td><%= a.year %></td> 
    <td><%= (a.id || 0 rescue 0) %></td> 
    <td><%= (a.data || 0 rescue 0) %></td> 
    <td><%= (@b.select{|h| h if h["year"] == a.year }.first.id || 0 rescue 0) %></td> 
    <td><%= (@b.select{|h| h if h["year"] == a.year }.first.data || 0 rescue 0) %></td> 
    <td><%= (@c.select{|h| h if h["year"] == a.year }.first.id || 0 rescue 0) %></td> 
    <td><%= (@c.select{|h| h if h["year"] == a.year }.first.data || 0 rescue 0) %></td> 
    <td><%= (@d.select{|h| h if h["year"] == a.year }.first.id || 0 rescue 0) %></td> 
    <td><%= (@d.select{|h| h if h["year"] == a.year }.first.data || 0 rescue 0) %></td> 
</tr> 
<% end %> 
</table> 

Se il @a non contiene tutti gli anni poi basta provare a fonderlo da

years = ((@a.collect{|h| h["year"]}) + (@b.collect{|h| h["year"]}) + (@c.collect{|h| h["year"]}) + (@d.collect{|h| h["year"]})).uniq 

poi si può semplicemente scorrendo anni array come:

<% years.each do |year| %> 
    <tr> 
     <td><%= year %></td> 
     <td><%= (@a.select{|h| h if h["year"] == year }.first.id || 0 rescue 0) %></td> 
     <td><%= (@a.select{|h| h if h["year"] == year }.first.data || 0 rescue 0) %></td> 
     <td><%= (@b.select{|h| h if h["year"] == year }.first.id || 0 rescue 0) %></td> 
     <td><%= (@b.select{|h| h if h["year"] == year }.first.data || 0 rescue 0) %></td> 
     <td><%= (@c.select{|h| h if h["year"] == year }.first.id || 0 rescue 0) %></td> 
     <td><%= (@c.select{|h| h if h["year"] == year }.first.data || 0 rescue 0) %></td> 
     <td><%= (@d.select{|h| h if h["year"] == year }.first.id || 0 rescue 0) %></td> 
     <td><%= (@d.select{|h| h if h["year"] == year }.first.data || 0 rescue 0) %></td> 
    </tr> 
    <% end %> 
    </table> 

Answer 2

Probabilmente significa questo nella vostra vista:

<% 
    A = @a.group_by{|a| a.year} 
    B = @b.group_by{|b| b.year} 
    C = @c.group_by{|c| c.year} 
    D = @d.group_by{|d| d.year} 
%> 

<table> 
    <% A.each do |year, a| %> 
    <% b = B[year] %> 
    <% c = C[year] %> 
    <% d = D[year] %> 
    <tr> 
     <td><%= year %></td> 
     <% if a.blank? %> 
     <td>0</td> 
     <td>0</td> 
     <% else %> 
     <%= a.id %> 
     <%= a.data %> 
     <% end %> 
     <% if b.blank? %> 
     <td>0</td> 
     <td>0</td> 
     <% else %> 
     <td><%= b.id %></td> 
     <td><%= b.data %></td> 
     <% end %> 
     <% if c.blank? %> 
     <td>0</td> 
     <td>0</td> 
     <% else %> 
     <td><%= c.id %></td> 
     <td><%= c.data %></td> 
     <% end %> 
     <% if d.blank? %> 
     <td>0</td> 
     <td>0</td> 
     <% else %> 
     <td><%= d.id %></td> 
     <td><%= d.data %></td> 
     <% end %> 
    </tr> 
    <% end %> 
</table> 

presumo qui @a contiene tutti gli anni altri array possono contenere (sulla base di query). Se non è il caso, devi prima creare una serie completa di anni:

<% years = (A.keys + B.keys + C.keys + D.keys).uniq %> 
<table> 
    <% years.each do |year| %> 
    <% a = A[year] %> 
    <!-- the rest is the same, as above --> 
    <% end %> 
</table> 

Answer 3

Nel controllore:

@results_by_year = Result.where(your_conditions).group_by(&:year) 
# this retrieves all the Result records wanted, without taking care of the record's `year` 

La struttura del hash sarà simile a questo:

# { 2010: [<Result id:1>, <Result id:3>], 
# 2012: [<Result id:2>], 
# 2014: [<Result id:7>, <Result id:9>] } 

Nella vista:

@results_by_year.each do |year, results| 
    = year 
    - results.each do |result| 
    = result.id 
    = result.data 
end